Datetime
All rules in this page can be applies to date
is leapyear
Input a date, validtes the input is in a leap year
RebbVal v = new RebbVal();
SimpleDateFormat ft = new SimpleDateFormat ("yyyy-MM-dd");
Date date = ft.parse("2020-05-01");
v.val(date, "is leapyear"); // truelet v = new RebbVal();
v.val(new Date("2020-05-01"), "is leapyear"); //true
v.val(v.year("2000"), "is leapyear"); // truev.val(v.year("2000"), "is leapyear")); //true// Java implementation does not support integer as year// in JavaScript, you can use a interger as year
v.val(2020, "is leapyear"); // trueis leapday
Take a date as input, validates the input is a leap day
SimpleDateFormat ft = new SimpleDateFormat ("yyyy-MM-dd");
Date date = ft.parse("2000-02-29");
assertTrue(v.val(date, "is leapyear"));v.val(new Date("2020-02-29"), "is leapday"); //trueAlso see
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